ok
ko vay
mắt
5,0004 ha ban nhe
90
4
gửi bạn nhé
Giả thiết: ΔABC vuông tại A, tia phân giác của góc ABC cắt cạnh AC tại H. Từ H vẽ HM ⊥ BC tại M.
Chứng minh:
Vì các cạnh và góc tương đương, ta có thể kết luận ΔABH = ΔMBH theo định lý cạnh-cạnh-cạnh (CCS).
Giả thiết: ΔABC vuông tại A, tia phân giác của góc ABC cắt cạnh AC tại H. Từ H vẽ HM ⊥ BC tại M. Gọi N là giao điểm của tia BA và tia MH.
Chứng minh:
Giả thiết: ΔABC vuông tại A, tia phân giác của góc ABC cắt cạnh AC tại H. Từ H vẽ HM ⊥ BC tại M. Gọi N là giao điểm của tia BA và tia MH.
Chứng minh:
Vì HB cắt NC tại góc vuông, ta có HB ⊥ NC.
tôi nghĩ thế
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