\(2009-\left(4\frac{5}{9}+x-7\frac{7}{8}\right):15\frac{3}{2}=2008\)

\(\Leftrightarrow2009-\left(\frac{41}{9}+x-\frac{63}{8}\right):\frac{33}{2}=2008\)

\(\Leftrightarrow2009-\left(x-\frac{239}{72}\right):\frac{33}{2}=2008\)

\(\Leftrightarrow2009-\frac{2x}{33}+\frac{239}{1188}=2008\)

\(\Leftrightarrow\frac{-2x}{33}=\frac{-1427}{1188}\)

\(\Leftrightarrow-2376x=-47091\)

\(\Leftrightarrow x=\frac{1427}{72}\)

ú chị to đi,

\(x+\frac{15}{7}=\frac{9}{2}\)

\(x=\frac{9}{2}-\frac{15}{7}=\frac{33}{14}\)

\(x-\frac{3}{4}=\frac{7}{2}\)

\(x=\frac{7}{2}+\frac{3}{4}=\frac{17}{4}\)

\(x.\frac{7}{8}=\frac{12}{5}\)

\(x=\frac{12}{5}:\frac{7}{8}=\frac{96}{35}\)

\(\frac{5}{6}:x=\frac{4}{3}\)

\(x=\frac{5}{6}:\frac{4}{3}=\frac{5}{8}\)

• a) x=9/2-15/7=33/14
• b) x=7/2+3/4=17/4
• c) x=12/5:7/8=61/35
• d) x=5/6:4/3=5/8
• k nha

a)\(\frac{27}{5}\text{x}\frac{91}{12}\text{x}\frac{125}{9}\text{x}\frac{96}{13}=\frac{27}{9}\text{x}\frac{91}{13}\text{x}\frac{125}{5}\text{x}\frac{96}{12}=3\text{x}7\text{x}25\text{x}8\)

Đến đây tự tính nha !

b)\(\frac{2539}{35}\text{x}\frac{7}{90}+\frac{561}{35}\text{x}\frac{7}{90}=\frac{7}{90}\text{x}\left(\frac{2539}{35}+\frac{561}{35}\right)=\frac{7}{90}\text{x}\frac{3100}{35}=\frac{3100}{90}\text{x}\frac{7}{35}=\frac{310}{9}\text{x}\frac{1}{5}=\frac{62}{9}\)

1. 27/5 x 91/12 x 125/9 x 96/13

2. 2539/35 x 7/90 + 561/35 x 7/90

3. 31/7 : (2/5 x 31/7)

4. (29 x 15/23 x 36/29) : 5/23

a) \(\frac{11}{15}+\frac{5}{7}+\frac{2}{7}+\frac{4}{15}=\left(\frac{11}{15}+\frac{4}{15}\right)+\left(\frac{5}{7}+\frac{2}{7}\right)\)

\(=2\)

b) \(\frac{5}{9}\times\frac{1}{2}\times\frac{5}{9}\times\frac{6}{4}=\frac{25}{81}\times\frac{3}{4}=\frac{25}{108}\)

c) \(\frac{7}{8}\div\frac{1}{2}+\frac{9}{8}\div\frac{1}{2}=\left(\frac{7}{8}+\frac{9}{8}\right)\div\frac{1}{2}\)

\(=2\div\frac{1}{2}=4\)

d) \(\frac{17}{10}+\frac{1}{2}-\frac{7}{10}=\left(\frac{17}{10}-\frac{7}{10}\right)+\frac{1}{2}\)

\(=1+\frac{1}{2}=\frac{3}{2}\)

a) \(\frac{11}{15}+\frac{5}{7}+\frac{2}{7}+\frac{4}{15}\)

\(=\left(\frac{11}{15}+\frac{4}{15}\right)+\left(\frac{5}{7}+\frac{2}{7}\right)\)

\(=1+1\)

\(=2\)

b) \(\frac{5}{9}.\frac{1}{2}.\frac{5}{9}.\frac{6}{4}\)

\(=\left(\frac{5}{9}\right)^2\left(\frac{1}{2}.\frac{6}{4}\right)\)

\(=\frac{25}{81}.\frac{3}{4}\)

\(=\frac{25}{108}\)

c) \(\frac{7}{8}:\frac{1}{2}+\frac{9}{8}:\frac{1}{2}\)

\(=\frac{7}{8}.2+\frac{9}{8}.2\)

\(=2\left(\frac{7}{8}+\frac{9}{8}\right)\)

\(=2.\frac{16}{8}\)

\(=2.2\)

\(=4\)

d) \(\frac{17}{10}+\frac{1}{2}-\frac{7}{10}\)

\(=\left(\frac{17}{10}-\frac{7}{10}\right)+\frac{1}{2}\)

\(=1+\frac{1}{2}\)

\(=\frac{2}{2}+\frac{1}{2}\)

\(=\frac{3}{2}\)

x=17,69444444    

x=1309/72

\(2009-\left(4\frac{5}{9}+x-7\frac{7}{18}\right):15\frac{2}{3}=2008\)

\(2009-\left(\frac{41}{9}+x-\frac{133}{18}\right):\frac{47}{3}=2008\)

\(\left(\frac{41}{9}+x-\frac{133}{18}\right):\frac{47}{3}=2009-2008\)

\(\left(\frac{41}{9}+x-\frac{133}{18}\right):\frac{47}{3}=1\)

\(\frac{41}{9}+x-\frac{133}{18}=1\cdot\frac{47}{3}\)

\(\frac{41}{9}+x-\frac{133}{18}=\frac{47}{3}\)

\(\frac{41}{9}+x=\frac{133}{18}+\frac{47}{3}\)

\(\frac{41}{9}+x=\frac{415}{18}\)

               \(x=\frac{415}{18}-\frac{41}{9}\)

                \(x=\frac{37}{2}\)

\(2009-\left(4\frac{5}{9}+x-7\frac{7}{18}\right)\div15\frac{2}{3}=2008\)

\(\left(4\frac{5}{9}+x-7\frac{7}{18}\right)\div15\frac{2}{3}=2009-2008\)

\(\left(-3\frac{3}{18}+x\right)\div15\frac{2}{3}=1\)

\(-3\frac{3}{18}+x=15\frac{2}{3}\)

\(x=15\frac{2}{3}+3\frac{3}{18}\)

\(x=15\frac{12}{18}+3\frac{3}{18}\)

\(x=18\frac{15}{18}\)

exactly 100%

a,(11/15+4/15)+(5/7+2/7)

=1+1

=2

b,5/9x(1/2+6/4)

=5/9x2

=10/9

c,1/2:(7/8+9/8)

=1/2:2

=1

d,(17/10-7/10)+1/2

=1+1/2

=3/2

a ) (11/15+4/15 ) + ( 5/7 +2 /7 )

=1+1

= 2

b)5/9 x ( 1/ 2 + 6/ 4 )

= 5/9 x 2

=10/9 

c) 17/10-5/10-7/10

=(17-5-7) / 10

= 5/10