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thế kỷ 8 TCN

Ta có: \(15 \frac{1}{17} = \frac{256}{17}\); \(29 \frac{16}{17} = \frac{509}{17}\). Tổng phải tìm là:
      \(\frac{256 + 257 + 258 + . . . + 507 + 508 + 509}{17} - \left(\right. 16 + 17 + 18 + . . . + 27 + 28 + 29 \left.\right)\)
\(= \frac{\left(\right. 256 + 509 \left.\right) 254}{2.17} - \frac{\left(\right. 16 + 29 \left.\right) 14}{2}\)
\(= 45.127 - 45.7\)
\(= 45.120\)
\(= 5400\)

Ta có: \(15 \frac{1}{17} = \frac{256}{17}\); \(29 \frac{16}{17} = \frac{509}{17}\). Tổng phải tìm là:
      \(\frac{256 + 257 + 258 + . . . + 507 + 508 + 509}{17} - \left(\right. 16 + 17 + 18 + . . . + 27 + 28 + 29 \left.\right)\)
\(= \frac{\left(\right. 256 + 509 \left.\right) 254}{2.17} - \frac{\left(\right. 16 + 29 \left.\right) 14}{2}\)
\(= 45.127 - 45.7\)
\(= 45.120\)
\(= 5400\)

Ta có: \(15 \frac{1}{17} = \frac{256}{17}\); \(29 \frac{16}{17} = \frac{509}{17}\). Tổng phải tìm là:
      \(\frac{256 + 257 + 258 + . . . + 507 + 508 + 509}{17} - \left(\right. 16 + 17 + 18 + . . . + 27 + 28 + 29 \left.\right)\)
\(= \frac{\left(\right. 256 + 509 \left.\right) 254}{2.17} - \frac{\left(\right. 16 + 29 \left.\right) 14}{2}\)
\(= 45.127 - 45.7\)
\(= 45.120\)
\(= 5400\)