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21 tháng 7 2023

\(...=\dfrac{21}{5}-\dfrac{2}{3}=\dfrac{63}{15}-\dfrac{10}{15}=\dfrac{53}{15}\)

AH
Akai Haruma
Giáo viên
21 tháng 7 2023

Lời giải:

$4\frac{1}{5}-\frac{2}{3}=\frac{53}{15}$

13 tháng 9 2017

a)1/3+1/4+2/3+3/4

=(1/3+2/3)+(1/4+3/4)

=1+1

=2.

b)1/2+1/3-1/5+1/6

=(1/2+1/3+1/6)-1/5

=1-1/5

=4/5

c)2/3x4/5+1/3x4/5

=4/5x(2/3+1/3)

=4/5x1

=4/5

d)2/3x4/5-1/3x4/5

=4/5x(2/3-1/3)

=4/5x1/3

=4/15

13 tháng 9 2017

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9 tháng 6 2023

a,  \(2\dfrac{1}{3}+4\dfrac{1}{5}+4\dfrac{1}{3}\)

\(=\dfrac{7}{3}+\dfrac{21}{5}+\dfrac{13}{3}\)

\(=\dfrac{1}{3}\left(7+13\right)+\dfrac{21}{5}\)

\(=\dfrac{20}{3}+\dfrac{21}{5}=\dfrac{100+63}{15}=\dfrac{163}{15}\)

b, \(5\dfrac{3}{4}-4\dfrac{1}{2}.3\dfrac{7}{8}\)

\(=\dfrac{23}{4}-\dfrac{9}{2}.\dfrac{31}{8}\)

\(=\dfrac{23}{4}-\dfrac{279}{16}=\dfrac{92-279}{16}=-\dfrac{187}{16}\)

c, \(1\dfrac{1}{2}.3\dfrac{2}{3}.4\dfrac{3}{4}\)

\(=\dfrac{3}{2}.\dfrac{11}{3}.\dfrac{19}{4}=\dfrac{209}{8}\)

d, \(6\dfrac{4}{5}:2\dfrac{3}{4}:1\dfrac{1}{2}\)

\(=\dfrac{34}{5}:\dfrac{11}{4}:\dfrac{3}{2}\)

\(=\left(\dfrac{34}{5}.\dfrac{4}{11}\right).\dfrac{2}{3}=\dfrac{136}{55}.\dfrac{2}{3}=\dfrac{272}{165}\)

 

11 tháng 10 2023

   [4\(\dfrac{1}{5}\) - 2\(\dfrac{2}{5}\)] x 8\(\dfrac{5}{6}\)

= [\(\dfrac{21}{5}\) - \(\dfrac{12}{5}\)] x \(\dfrac{53}{6}\)

\(\dfrac{9}{5}\) x \(\dfrac{53}{6}\)

\(\dfrac{159}{10}\)

11 tháng 10 2023

   [5\(\dfrac{1}{3}\) - 2\(\dfrac{2}{3}\)]: \(\dfrac{3}{7}\)

= [\(\dfrac{16}{3}\) - \(\dfrac{8}{3}\)]: \(\dfrac{3}{7}\)

\(\dfrac{8}{3}\) : \(\dfrac{3}{7}\)

\(\dfrac{56}{9}\)

20 tháng 5 2018

 \(=\frac{9}{7}+\frac{23}{6}+\frac{23}{4}-\frac{63}{562}\)\(\frac{205}{532}:\frac{41}{3}\)

\(=\frac{215}{42}+\frac{23}{4}-\frac{1845}{42712}:\frac{41}{3}\)

\(=\frac{913}{84}-\frac{135}{42712}\)

\(=10,86588691...\)

17 tháng 8 2017

1 - 2 + 3 = 1 

1 - 2 - 3 + 4 = 1

Bạn thử hết các dấu đi

17 tháng 8 2017

(1+2):3=1

1x2+3-4=1

1-2+3+4-5=1

(1x2+3-4+5):6=1

(1-2+3+4-5+6):7=1

[(1x2+3-4+5):6+7]:8=1

14 tháng 6 2015

a)\(\frac{4}{3.7}+\frac{4}{7.11}+...+\frac{4}{23.27}=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{23}-\frac{1}{27}=\frac{1}{3}-\frac{1}{27}=\frac{8}{27}\)

b)\(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{6.7}=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{6}-\frac{1}{7}=\frac{1}{2}-\frac{1}{7}=\frac{5}{14}\)

c)\(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{11.13}+\frac{2}{1.2}+\frac{2}{2.3}+...+\frac{2}{9.10}=\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{11}-\frac{1}{13}\right)+2\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)

\(=\frac{1}{3}-\frac{1}{13}+2\left(1-\frac{1}{10}\right)=\frac{10}{39}+\frac{9}{5}=\frac{401}{195}\)

26 tháng 9 2019

a, 100/5

b,120/5

10 tháng 6 2017

a) = 29/15

b) = 7/15

c) = 1

d) = 3

e) = 67/17

f) = 2

mk nhanh nhất tk cho mk nha

10 tháng 6 2017

a/\(\frac{3}{5}+\frac{4}{3}=\frac{9}{15}+\frac{20}{15}=\frac{29}{15}\)

b/\(\frac{2}{3}-\frac{1}{5}=\frac{10}{15}-\frac{3}{15}=\frac{7}{15}\)

c/\(\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=\frac{3}{6}+\frac{2}{6}+\frac{1}{6}=\frac{7}{6}\)

d,\(\frac{3}{5}+\frac{4}{7}+\frac{7}{5}+\frac{3}{7}=\left(\frac{3}{5}+\frac{7}{5}\right)+\left(\frac{4}{7}+\frac{3}{7}\right)=2+1=3\)

8 tháng 9 2017

1:2/5x1/2

=5/2x1/2

=5/4

1/3x2/3-1/4

=2/9-1/4

=-1/36

1/2/3+2/4/5

=5/3+14/5         

=67/15

3/1/2x1/4/5

=7/2x9/5

=63/10

1/4/7-2/3

=11/7-2/3

=19/21